- 2.3 Differentiabilityap Calculus Test
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Differentiable means that the derivativeexists ..
Lesson 2.6: Diﬀerentiability: Afunctionisdiﬀerentiable at a point if it has a derivative there. In other words: The function f is diﬀerentiable at x if.
Posted by 3 years ago. Can someone help me with this question? (Ap Calc AB - Graphing/differentiability) Ap calculus. Differentiate any function with our calculus solver. Enter an expression and the variable to differentiate with respect to. Then click the Differentiate button. FREE-RESPONSE SOLUTIONS 2019 AB Question AB-2 (a) vtP is differentiable and therefore continuous on 0.3,2.8.Since 2.8 0.3 55 55 0 2.8 0.3 2.5 vvPP. Its derivative is (1/3)x −(2/3) (by the Power Rule) At x=0 the derivative is undefined, so x (1/3) is not differentiable. At x=0 the function is not defined so it makes no sense to ask if they are differentiable there.
Example: is x2 + 6x differentiable?
Derivative rules tell us the derivative of x2 is 2x and the derivative of x is 1, so:
Its derivative is 2x + 6
So yes! x2 + 6x is differentiable.
.. and it must exist for every value in the function's domain.
In its simplest form the domain is
When not stated we assume that the domain is the Real Numbers.
For x2 + 6x, its derivative of 2x + 6 exists for all Real Numbers.
So we are still safe: x2 + 6x is differentiable.
But what about this:
Example: The function f(x) = x (absolute value):
|x looks like this:|
At x=0 it has a very pointy change!
Does the derivative exist at x=0?Format external hard drive for mac using windowslasopafs.
We can test any value 'c' by finding if the limit exists:
limh→0f(c+h) − f(c)h
Let's calculate the limit for x at the value 0:
The limit does not exist! To see why, let's compare left and right side limits:
The limits are different on either side, so the limit does not exist.
So the function f(x) = x is not differentiable
A good way to picture this in your mind is to think:
As I zoom in, does the function tend to become a straight line?
The absolute value function stays pointy even when zoomed in.
Here are a few more examples:
The Floor and Ceiling Functions are not differentiable at integer values, as there is a discontinuity at each jump. But they are differentiable elsewhere.
The Cube root function x(1/3)
Its derivative is (1/3)x−(2/3) (by the Power Rule)
At x=0 the derivative is undefined, so x(1/3) is not differentiable.
At x=0 the function is not defined so it makes no sense to ask if they are differentiable there.
To be differentiable at a certain point, the function must first of all be defined there!
As we head towards x = 0 the function moves up and down faster and faster, so we cannot find a value it is 'heading towards'.
So it is not differentiable.
But we can change the domain!
Example: The function g(x) = x with Domain (0,+∞)
The domain is from but not including 0 onwards (all positive values).
2.3 Differentiabilityap Calculus Test
Which IS differentiable.
And I am 'absolutely positive' about that :)
So the function g(x) = x with Domain (0,+∞) is differentiable.
We could also restrict the domain in other ways to avoid x=0 (such as all negative Real Numbers, all non-zero Real Numbers, etc).
Because when a function is differentiable we can use all the power of calculus when working with it.
When a function is differentiable it is also continuous.
Differentiable ⇒ Continuous
But a function can be continuous but not differentiable. For example the absolute value function is actually continuous (though not differentiable) at x=0.
(1) Find the derivatives of the following functions using first principle.
(i) f(x) = 6Solution
(ii) f(x) = -4x + 7Solution
(iii) f(x) = -x2 + 2 Solution
(2) Find the derivatives from the left and from the right at x = 1 (if they exist) of the following functions. Are the functions differentiable at x = 1?
(i) f(x) = x - 1 Solution
(ii) f(x) = √(1 - x2) Solution
(3) Determine whether the following function is differentiable at the indicated values.
(i) f(x) = x x at x = 0 Solution
(ii) f(x) = x2 - 1 at x = 1 Solution
(iii) f(x) = x + x - 1 at x = 0, 1 Solution
(iv) f(x) = sin x at x = 0 Solution
(4) Show that the following functions are not differentiable at the indicated value of x.
(5) The graph of f is shown below. State with reasons that x values (the numbers), at which f is not differentiable.
(6) If f(x) = x + 100 + x2, test whether f'(-100) exists.
(7) Examine the differentiability of functions in R by drawing the diagrams.
(i) sin x Solution
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(ii) cos x Solution
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